Contribute
| For The Mathematically Inclined |
Anil Saigal
07/02/2015
Problem #1
Problem #2
----------------------------------------------------------------------------------------------------------
Solution to Problems from 06/18/15
Solution:
59.
Problem #2
Solution:
69.
Congratulations to Swati Dave, Prem Kapoor and Saba Lateef, who were winners of the last set of puzzles.
Please send your solutions to mr.asaigal@gmail.com.
Use Problem Solutions M-0702815 as the subject line. Please include your full name in the text of the main message. Everyone with the right answer will be acknowledged in the next issue of Lokvani.
Please do not post your solution in Post Comments. No credit will be given for solutions not sent to anil@lokvani.com.
If you need clarification on any problem, please contact anil@lokvani.com.
--------------------------------------------------------------------------------------------------------
Solution to Problems from 06/18/15
Problem #1
Which is the smallest number which, when divided by 2, 3, 4, 5 and 6 will give 1, 2, 3, 4 and 5 as remainders, respectively?
Solution:
59.
The product of three consecutive odd numbers is 357,627. What is the smallest of the three?
Solution:
69.
Congratulations to Swati Dave, Prem Kapoor and Saba Lateef, who were winners of the last set of puzzles.
|
You may also access this article through our web-site http://www.lokvani.com/
