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| For The Mathematically Inclined |
Anil Saigal
06/18/2015
Problem #1
Which is the smallest number which, when divided by 2, 3, 4, 5 and 6 will give 1, 2, 3, 4 and 5 as remainders, respectively?
Problem #2
The product of three consecutive odd numbers is 357,627. What is the smallest of the three?
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Solution to Problems from 06/04/15
Solution:
8.
Problem #2
Solution:
2519.
Congratulations to Abhimanyu Bhargava, who was the winner of the last set of puzzles.
Please send your solutions to mr.asaigal@gmail.com.
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Solution to Problems from 06/04/15
Problem #1
Find the fifth term in the following series 77, 49, 36, 18, ...
Solution:
8.
If we set out by ranks of 10, we will be one short. We will also be one short if we set out by ranks of 9, 8, 7, 6, 5, 4, 3, and even 2. Yet there are fewer than 5000 participants. How many are we?
Solution:
2519.
Congratulations to Abhimanyu Bhargava, who was the winner of the last set of puzzles.
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