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For The Mathematically Inclined

Anil Saigal
06/18/2015

Problem #1
Which is the smallest number which, when divided by 2, 3, 4, 5 and 6 will give 1, 2, 3, 4 and 5 as remainders, respectively?

Problem #2
The product of three consecutive odd numbers is 357,627. What is the smallest of the three?


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Please send your solutions to mr.asaigal@gmail.com. 

Use Problem Solutions M-061815 as the subject line. Please include your full name in the text of the main message. Everyone with the right answer will be acknowledged in the next issue of Lokvani. 

Please do not post your solution in Post Comments. No credit will be given for solutions not sent to anil@lokvani.com. 

If you need clarification on any problem, please contact anil@lokvani.com. 

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Solution to Problems from 06/04/15

Problem #1
Find the fifth term in the following series 77, 49, 36, 18, ...

Solution:
8.

Problem #2
If we set out by ranks of 10, we will be one short. We will also be one short if we set out by ranks of 9, 8, 7, 6, 5, 4, 3, and even 2. Yet there are fewer than 5000 participants. How many are we?

Solution:
2519.

Congratulations to Abhimanyu Bhargava, who was the winner of the last set of puzzles.



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